Ok, here we go:
5 cars total.
1. Rachel - first car in line, yellow, SUV
2. blue car (Rachel is in front of the blue car), convertible, Anton
3. minivan - third car in line, Diego
4. white car, sedan, Ingrid
5. green car, immediately behind white car, Yuna, pickup
We know that Rachel is first, a blue car is second and the minivan is third. We know that 3, 4 cannot be a convertible since one is a minivan and the other is a sedan. We also know that a yellow car is in front of the convertible.
Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.
Fill in what you do know and start to eliminate the outliers. Hope that helps.
Answer:
Larger number = 32
Step-by-step explanation:
Smaller number = x
Larger number = y
y - x = 8 -----------(I)
3y = 4x ---------------(II)
3y/4 = x
Plug in x = 3y/4 in equation (I)
y = 8*4
y = 32
Plug in y = 32 in equation (II)
3y = 4x
3*32 = 4x
4x = 3*32
x = 
x = 3 *8
x = 24
Answer:
r= -19/5
Step-by-step explanation:
<h3>
Answer: 0.98976</h3>
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Explanation:
60% of the people have been vaccinated, so 40% have not.
The probability of getting five people in a row that aren't vaccinated is (0.40)^5 = 0.01024
Subtract this from 1 to get the probability of at least one vaccinated person in the sample of five.
1-0.01024 = 0.98976
This works because the events "at least one vaccinated" and "none vaccinated" are complementary. One or the other must happen, which means the two probabilities add to 1.
