Answer:
0.0035289
Step-by-step explanation:
From the question;
mean annual salary = $63,500
n = sample size = 31
Standard deviation = $6,200
Firstly, we calculate the z-score of $60,500
Mathematically;
z-score = x-mean/SD/√n = (60500-63500)/6200/√(31) = -2.6941
So we want to find the probability that P(z < -2.6941)
We can get this from the standard normal table
P( z < -2.6941) = 0.0035289
You simply have to sum the two fraction together to get the total amount of occupied plot. To do so, multiply both numerator and denominator of each fration by the same number, so that they end up having the same denominator.
You can multiply both numerator and denominator of 1/8 by 3 to get 3/24. Similarly, you can multiply both numerator and denominator of 1/6 by 4 to get 4/24.
Now we can easily sum the two fractions together:
So, if 7 parts out of 24 are occupied, it means that there are parts left for other crops. So, the answer is 17/24.
Answer:
oe hello im from nepal follow me plz bro
Answer:
111
Step-by-step explanation: