The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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Answer:
I dont know
Step-by-step explanation:
only doing it for points
Answer:
Step-by-step explanation:
The given differential equation is 
The characteristics equation is given by
Finding the values of r
We got a repeated roots. Hence, the solution of the differential equation is given by
On differentiating, we get
Apply the initial condition y (0)= 3 in equation (i)
Now, apply the initial condition y' (0)= 13 in equation (ii)
Therefore, the solution of the differential equation is
Answer:
hopefully this helps? please try
Answer:
x=7
Step-by-step explanation:
y=mx
5.5=m×11
5.5÷11=m
m=1/2
y=mx
3.5=1/2×x
3.5÷1/2=x
x=7
