I have no clue if this is correct but the answer I got was 10,260,000
Answer: $4,365.10
Step-by-step explanation:
Ok, we know that:
The account starts with $2350
There is a simple interest of 3.75% (or 0.035).
Then after one year, the amount in the account will increase by 3.75%, this means that the amount will be:
$2350 + 0.035*$2350 = (1.035)*$2350.
After another year, we have the same increase (but applied to the new amount in the account):
(1.035)*$2350 + 0.035*(1.035)*$2350. = (1.035)^2*$2350
And so on.
You already can see the pattern here, the amount of money in the saving account after N years will be:
M(N) = $2350*(1.035)^N.
Now we can answer:
what is the balance of the account if it earns a simple interest of 3.75% for 18 years?
Just replace N by 18 in that equation:
M(18) = $2350*(1.035)^18 = $4,365.10
-10 -10y = 10
+10 +10
-10y = 20
20/-10 = -2
Y = -2
Answer:
Therefore they are 734.106 miles apart.
Step-by-step explanation:
Given that ,
Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.
It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.
Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles
Then the distance between the ships = AC
We know
The sum of all angles = 180°
⇒∠A+∠B+∠C=180°
⇒∠A+135°40'+∠C=180°
⇒2∠A= 180°- 135°40' [ since ∠A=∠C]
⇒2∠A=44°60'
⇒∠A= 22°30'
Again we know that,
Taking last two ratio,
Putting the value of BC , AC ,∠A,∠B
≈734.106 miles
Therefore they are 734.106 miles apart.