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2 years ago

In the diagram, AC is a diameter of the circle with center 0. If m ZACB = 50°, what is ZBAC?

Mathematics

1 answer:

Snowcat [4.5K]2 years ago

7 0

Answer:

40degrees

Step-by-step explanation:

Find the diagram attached

Since the triangle ina semi circle is a right angle, hence <B = 90degrees

Also frm the diagram

<A + <B + <C = 180

<A + 90 + 50 = 180

<A + 140 = 180

<A = 180 - 140

<A = 40degrees

Hence the measure if m<BAC is 40degrees

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2 years ago

Classify ABC by its sides. Then determine whether it is a right triangle.

m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

$AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

AB = $\sqrt{(9-3)^{2}+(6-3)^{2} } = \sqrt{6^{2}+3^{2} } =\sqrt{45}$

Given vertices are B(6,9) and C( 6,-3)

$B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2} }$

= $\sqrt{(-3-9)^{2}+(6-6)^{2} } =\sqrt{12^{2} } = 12$

BC = 12

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$AC = \sqrt{(6-3)^{2}+(-3-3)^{2} } = \sqrt{9+36} = \sqrt{45}$

AC² = AB²+BC²

45 = 45+144

45 ≠ 189

∴Given Δ ABC is not a right angle triangle

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