What is the equilibrium constant expression for the given system?

Chemistry

1 answer:

artcher [175]2 years ago

5 0

<h3>Answer:</h3>

$\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}$

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Aqueous Solutions</u>

States of matter

<u>Kinetics</u>

Rate Laws

<u>Equilibrium</u>

Equilibrium Reactions RxN ⇄
Equilibrium Constants
Equilibrium Expression: $\displaystyle K = \frac{[Producst]^{coefficients}}{[Reactants]^{coefficients}}$

<h3>Explanation:</h3>

*Note: Only gases and liquids affect equilibrium

<u>Step 1: Define</u>

[RxN - Balanced] 2H₂O (g) ⇄ 2H₂ (g) + O₂ (g)

<u>Step 2: Identify</u>

[Reactant] H₂O

Coefficient of 2

[Product] H₂

Coefficient of 2

[Product] O₂

Coefficient of 1

<u>Step 3: Write K Expression</u>

Substitute: $\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}$

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Write a balanced half-reaction for the reduction of bismuth oxide ion to bismuth ion in basic aqueous solution. Be sure to add p

Butoxors [25]

Answer:

$3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$

Explanation:

Hello there!

In this case, according to the required half-reaction, we start by setting it up from bismuth (V) oxide ion to bismuth (III) ion:

$BiO_3^-\rightarrow Bi^{3+}$

Thus, next realize that the oxidation state of Bi in BiO3^- is 5+ because oxygen is 2- (-2*3+x=-1;x=-1+6;x=+5), so we obtain:

$(Bi^{5+}O_3)^-\rightarrow Bi^{3+}$

Thereafter, we realize three water molecules are needed on the right in order to balance the oxygens and consequently 6 hydrogen atoms on the left to balance hydrogen:

$6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O$

Now, since the balance is is basic media, we add six molecules of hydroxide ions in order to produce water with the hydrogen ones:

$6OH^-+6H^++(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+3H_2O+6OH^-\\\\6H_2O-3H_2O+(Bi^{5+}O_3)^-\rightarrow Bi^{3+}+6OH^-$