They have a band around them close to the ‘front end, ' sorry if this doesn't help, lol. :)
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
Answer: there are no solutions
Step by step: Step 1: Simplify both sides of the equation.
3
(
x
−
1
)
=
5
x
+
3
−
2
x
(
3
)
(
x
)
+
(
3
)
(
−
1
)
=
5
x
+
3
+
−
2
x
(Distribute)
3
x
+
−
3
=
5
x
+
3
+
−
2
x
3
x
−
3
=
(
5
x
+
−
2
x
)
+
(
3
)
(Combine Like Terms)
3
x
−
3
=
3
x
+
3
3
x
−
3
=
3
x
+
3
Step 2: Subtract 3x from both sides.
3
x
−
3
−
3
x
=
3
x
+
3
−
3
x
−
3
=
3
Step 3: Add 3 to both sides.
−
3
+
3
=
3
+
3
0
=
6
S answer is no for the question
Answer: 12b
Step-by-step explanation: you multiply 4 by 3 but keep the b