When we look at an ordered pair, it will be presented as (x,y)
The first term, x (called the x-coordinate), will tell us how far we should count outwards from 0 (The Origin). The second term, y (called the y-coordinate), will tell us how far we will count outwards from our x coordinate.
I hope this helps! If you would like me to elaborate more just let me know:)
Answer:
Domain = (-∞, -2) ∪ (-2, ∞).
Range = (-∞, 0) ∪ (0, ∞).
Step-by-step explanation:
t can't have the value -2 because that would make 1/(t + 2) = 1/0 which is undefined.
So the domain is All real values of t. except t = -2.
As t approaches infinity or negative infinity f(t) approaches zero, and as t approaches -2 from below or above f(t) approaches negative infinity or positive infinity.
Answer:
aₙ = 7n +29
Step-by-step explanation:
22 ; 15 ; 8; 1;........aₙ
aₙ = -7n +29
<span>The
associative rule is a rule about when it's safe to move parentheses
around. You can remember that because the parentheses determine which
expressions you have to do first--which numbers can associate with each
other. It looks like this:
For addition: (a + b) + c = a + (b + c)
For multiplication: (ab)c = a(bc)
The commutative property is about which operations you can do backward
and forward. You can remember this by thinking of people commuting to
work: they go to work every morning, then they repeat the same operation
backward when they commute home. It looks like this:
For addition: a + b = b + a
For multiplication: ab = ba
Finally, the distributive property tells you what happens when you
distribute one operation against another kind in parentheses. It looks
like this:
a * (b + c) = ab + ac
In other words, the a is "distributed" over the b and c.
Of course, you can make these work together:
a * (b + (c + d))
= a * ((b + c) + d) (by the associative property)
= a * (d + (b + c)) (by the commutative property)
= ad + a (b + c) (by the distributive property)
= ad + ab + ac (by the distributive property again).
Hope this helps. </span>
A is one solution
Sorry this is all I could I help you with good luck
