Answer:
10
Step-by-step explanation:
Answer:3/9
Step-by-step explanation:
Answer:
we have the expression as;
1/sin u cos u
Step-by-step explanation:
tan u = sin u/cos u
cot u = cos u/sin u
Thus;
sin u/cos u + cos u/sin u
The lcm is sin u cos u
Thus, we have that;
(sin^2 u + cos^2 u)/sin u cos u
But ; sin^2 u + cos^2 u = 1
so we have ;
1/sin u cos u
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Answer:
-3x^6 -x^4 +2x^3 -8x +8
Step-by-step explanation:
Use the distributive property 4 times.
(-3x^3 + 2x - 4)×(x^3 + x - 2)
= -3x^3(x^3 +x -2) +2x(x^3 +x -2) -4(x^3 +x -2) . . . . once
= -3x^6 -3x^4 +6x^3 +2x^4 +2x^2 -4x -4x^3 -4x +8 . . . . 3 more times
= -3x^6 +x^4(-3+2) +x^3(6 -4) +2x^2 +x(-4 -4) +8 . . . . group like terms
= -3x^6 -x^4 +2x^3 -8x +8
