Answer:
Step-by-step explanation:
a1 = - 2
an = a1 * r^(n - 1)
a6 = -486
-486 = - 2 * r^(6-1) Divide by 2
243 = r^5
The largest value that r could be is 3.
4^5 = 1024
(243)^(1/5) = 3
So the general formula
an = -2*(3)^(n - 1)
Let A= <span>2 – 11x2 – 8x + 6x2, the standard form of A is
A = - 5x² -8x + 2
</span>
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Find his rate:
120 / 15 = $8 per hour
Multiply the rate by hours:
$8 x 20 hours = $160
He will earn $160
Answer:
C
Step-by-step explanation:
a (5) = c (4)
5 x 4 = 20
20 (total) divided by the 5 apples is $4.