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Alekssandra [29.7K]

2 years ago

12

The area of Shawn's bedroom is 110 square feet. He places his bed, which is 7 feet long and 5 feet wide, in one corner of the be

droom. How much space will Shawn have left?

1 answer:

vagabundo [1.1K]2 years ago

6 0

Answer:

gggg

Step-by-step explanation:

duxufif8fis5durris5is

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Express 2x2 – 3x – 5 as the product of two binomial factors.

sergeinik [125]

Answer:

<h3>(2x-5) (x+1)</h3>

Step-by-step explanation:

Express 2x2 – 3x – 5 as the product of two binomial factors.

factorize the given expression

2x^2 – 3x – 5

2x^2 – 5x+2x – 5

x(2x-5)+ 1 (2x-5)

(2x-5) (x+1)

Hence the expression as the product of two binomial is (2x-5) (x+1)

6 0

2 years ago

Scott is four more than double the age of Todd. Scott is 56. What is Todd's age?

SSSSS [86.1K]

Answer: 26 years old

Step-by-step explanation:

Since Scott is four more than double the age of Todd, start by taking away four from Scott's age.

56-4=52

Then take half of that because that would be double of Todd's age

52/2=26

Todd is 26 years old.

5 0

1 year ago

Which step is included in the constitution of inscribed polygons?

Morgarella [4.7K]

I don't know.

you should do it your self not with the internet

3 0

2 years ago

The scatter plot shows the number of absences in a week for classes of different sizes. Trevor concluded that there is a positiv

QveST [7]

This is right the answer is A.

8 0

2 years ago

En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Nonamiya [84]

Answer:

$\displaystyle \tan A=\frac{4}{3}$

Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

$sen^2A+cos^2A=1$

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

$cos^2A=1-sen^2A$

Sustituyendo:

$\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2$

$\displaystyle cos^2A=1-\frac{16}{25}$

$\displaystyle cos^2A=\frac{25-16}{25}$

$\displaystyle cos^2A=\frac{9}{25}$

Tomando raíz cuadrada:

$\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}$

La tangente se define como:

$\displaystyle \tan A=\frac{sen\ A}{cos\ A}$

Substituyendo:

$\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}$

$\displaystyle \tan A=\frac{4}{3}$

6 0

2 years ago