We have been given that :-
The length of a parasite in experiment A is 
The length of a parasite in experiment B is 
Let us write the the length of the parasite in experiment A in the exponent of -3.
Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.
The difference in the length is given by
Therefore, the length of the parasite in experiment A is inches greater than the length of the parasite in experiment B.
Answer:
The answer I believe is : D.
~ Hope this is correct, if I'm wrong I'm sorry, have a gr8 day/ night my friend!~
Step-by-step explanation:
Answer:
x = (y - b)/m
Step-by-step explanation:
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First subtract b from both sides:
y = mx + b
y (-b) = mx + b (-b)
y - b = mx
Next, divide m from both sides:
(y - b)/m = (mx)/m
x = (y - b)/m
x = (y - b)/m is your answer.
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Answer:
185.68 cm3
Step-by-step explanation:
SA = 2 (L x W) + 2 (L x H) + 2 (W x H)
= 2 (8.2 x 3.4) + 2 (8.2 x 5.6) + 2 (3.4 x 5.6)
= 2 (27.88) + 2 (45.92) + 2 (19.04)
= 55.76 + 91.84 + 38.08
SA = 185.68 cm3
