Answer:
$171
Step-by-step explanation:
=PRN
950×0.06×3
hope this helps and makes sense :))
Answer:
Step-by-step explanation:
Given: There are 2 classes of 25 students.
13 play basketball
11 play baseball.
4 play neither of sports.
Lets assume basketball as "a" and baseball as "b".
We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)
As given total number of student is 25
Now, subtituting the values in the formula.
⇒P(a∪b)=
taking LCD as 25 to solve.
⇒P(a∪b)=
∴ P(a∪b)=
Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is .
Answer:
this is questions in class 10ICSE mathematics chapter linear equations
For this case we have the following diagonals:
AE = 40
ST = x + 5
The intersection of the diagonals occurs when:
AE = ST
Therefore, matching we have:
40 = x + 5
Clearing x we have:
x = 40-5
x = 35
Answer:
The value of x is:
x = 35