<span>68=-16t2+64t+8
16t2-64t+60=0
4t2-16t+15=0
(2t-5)(2t-3)=0
t=5/2 or 3/2
The object is at 68 feet after 3/2 secs, and returns to 68 feet after another second..</span>
The answer is zero point four three
You could also write this answer as 0.43
Answer:
umm here..i don't know if it's right but there....you can download mathpapa and goodluck
The answer is 1/2 in fraction form because 0.5 is half of 1
Answer:
Part A) x=9 and m∠FGH=29°
Part B) m∠HGI=29°
Part C) m∠FGI=58°
Step-by-step explanation:
Part A) Solve for x and find m∠FGH
we know that
m∠FGI=m∠FGH+m∠HGI
If GH bisects FGI
then
m∠FGH=m∠HGI
substitute the values
4x-7=5x-16
solve for x
5x-4x=16-7
x=9
m∠FGH=4x-7
m∠FGH=4(9)-7=29°
Part B) Find the measure of angle HGI
m∠HGI=5x-16
Remember that
m∠FGH=m∠HGI
Verify
m∠HGI=5(9)-16=29° -----> is correct
Part C) Find the measure of angle FGI
m∠FGI=m∠FGH+m∠HGI
substitute the values
m∠FGI=29°+29°=58°