Answer is: there is 2,69·10²³ atoms of bromine.
m(CH₂Br₂) = 39,0 g.
n(CH₂Br₂) = m(CH₂Br₂) ÷ M(CH₂Br₂).
n(CH₂Br₂) = 39 g ÷ 173,83 g/mol.
n(CH₂Br₂) = 0,224 mol.
In one molecule of CH₂Br₂, there is two bromine atoms, so:
n(CH₂Br₂) : n(Br) = 1 : 2.
n(Br) = 0,448 mol.
N(Br) = n(Br) · Na.
N(Br) = 0,448 mol · 6,022·10²³ 1/mol.
n(Br) = 2,69·10²³.
To answer this question a balanced chemical equation is necessary. The correct equation is: N2 + 3H2 = 2NH3
From this equation, one mole of nitrogen react with 3 moles of hydrogen to give 2 moles of ammonia.
Therefore, the mole ratio of NH3 to N2 is 2:1
there are 8 moon phases.
They are - First quarter, waxing crescent, new, waning crescent, third quarter, Waning gibbous, full, and waxing gibbous
The rate of change in velocity<span> is called acceleration.</span>
Answer:
30.34g (corrected to 4 significant figures).
Explanation:
Take the atomic mass of C=12.0, H=1.0, O=16.0.
no. of moles = mass / molar mass
So, no. of moles of butane reacted = 10 / (12x4 + 1x10)
= 0.172414 mol
Since O2 is in excess and butane is the limiting reagent, the no. of moles of carbon dioxide produced depends on the no. of moles of butane reacted.
From the equation, the mole ratio of butane:Carbon dioxide = 2: 8 = 1: 4,
meaning 1 mole of butane gives 4 moles of CO2.
Using this ratio,
we can deduce that the no. of moles of CO2 produced = 0.172414 x 4
=0.689655 mol
As mass = no. of moles x molar mass
mass of CO2 produced = 0.689655 x (12.0+16.0x2)
=30.34g (corrected to 4 significant figures).