Given:
In a right angle triangle ABC, altitude BD drawn to hypotenuse AC.
AD=3 and, AC=27.
To find:
The length of AB.
Solution:
Draw a figure by using the given information as shown below.
In triangle ABC and ADB,
(Right angles)
(Common angle)
(AA similarity postulate)
We know that the corresponding parts of congruent triangles are proportional. So,
After substituting the given values, we get
Taking square root on both sides, we get
Therefore, the length of AB is 9 units.
A(-6,4) and E(6,0)
slope m = (4 - 0) / ( -6-6) = 4/-12 = -1/3
perpendicular, slope is opposite and reciprocal so slope = 3
A perpendicular bisector<span> of a </span>line<span> segment is a </span>line <span>segment </span>perpendicular<span> to and passing through the midpoint
</span>Midpoint:
so x = ((-6+6)/2 = 0 and y = (4+0)/ 2 = 2
so M = (0,2)
equation of perpendicular line: y = 3x + 2
answer:
equation: y = 3x + 2
point lies on perpendicular bisector: (0,2)
Answer:
![\sqrt[2]{4^3}](https://tex.z-dn.net/?f=%5Csqrt%5B2%5D%7B4%5E3%7D)
Step-by-step explanation:
4 ^ (3/2)
The bottom of the fraction is the index and the top is the power
Answer:
-1+2-4+8-10+12-14+16-18+20
=
-47+68
= +21
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