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2 years ago

What can graphs be used for?

Mathematics

1 answer:

enot [183]2 years ago

7 0

Answer:

D. All of the above.

Step-by-step explanation: Please brainliest if correct!

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Do i begin with division first?

lara31 [8.8K]

Use PEMDAS. Division comes before addition. start with 9/25 ÷ 18/15. You will divide those like you would normally divide a fraction, so yes, do the inverse of 18/15 and multiply that by 9/25. after you've done that, take that answer and add the 5/8 to it.
:)

5 0

2 years ago

Read 2 more answers

Koalas sleep for 20hours a day. For what fraction of a day do koalas sleep?

vagabundo [1.1K]

Answer:

5/6

Step-by-step explanation:

There are 24 hours a day and a koala sleeps for 20 hours of it:

20/24

5/6

5 0

2 years ago

Read 2 more answers

What is the 308th term of the sequence 11,12.5,14,15.5,17...

Alecsey [184]

$\huge\boxed{471.5}$

The formula for an arithmetic sequence is as follows:

$a_n=a_1+(n-1)d$

In this formula, $a_n$ represents the $n$ th term of the sequence and $d$ represents the common difference between each term.

Plug in the known values.

$a_{308}=11+(308-1)1.5$

Subtract.

$a_{308}=11+307*1.5$

Multiply.

$a_{308}=11+460.5$

Add.

$a_{308}=\boxed{471.5}$

6 0

2 years ago

Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2

drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is $x^{3}-2 x^{2}-x+2=0$

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is

$F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0$

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

$F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0$

$\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}$

So, the equation is $x^{3}-2 x^{2}-x+2=0$

Let us put x = 0 in f(x) to check whether our answer is correct or not.

$\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2$

Hence, the equation of the polynomial is $x^{3}-2 x^{2}-x+2=0$

3 0

2 years ago

If f(x)=-2x-6, then f^-1(x)

iVinArrow [24]

$y=-2x-6. \newline y^{-1}=\frac{1}{2}(-y-6).$

7 0

2 years ago