I don't what form of measurement to use (like grams, cusp, etc.) but I'm pretty sure it'd be cups
I think it's 5/96 or .05208333
So, 5/8 is .625. Dividing that up in throwing it into 12 cupcakes.
-6/7 because it’s rise over run, we are going down so it’s negative, 10 down and 9 to the left which is -0.9 and -6/7 it’s -0.857 and if we round this number we have -0.9 left
Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Answer:
The function h(x) is decreasing on the interval (3, ∞).
Step-by-step explanation:
Please take a look at the attached image.
You will see a graph of the given function h(x) = -2. The function is decreasing.
The function starts at 3 and starts to go towards negative infinity on the x-axis. Therefore the function is decreasing on the interval (3, ∞).
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Step(1)
To find q(a) we just need to put a instead of x in q(x) function.
Let's do it...
Multiply sides by -2 :
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Step (2)
To find q(a+1) we just need to put a+1 instead of x in q(x) function.
Let's do it...
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Step (3)
And we're done.
Thanks for watching buddy good luck.
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