The first given equation is:
4x + 3y = 6
which can be rewritten as:
2(2x) + 3y = 6 .............> equation I
The second given equation is:
2x + 2y = 5
which can be rewritten as:
2x = 5 - 2y ........> equation II
Substitute with equation II in equation I to get the value of y as follows:
2(5-2y) + 3y = 6
10 - 4y + 3y = 6
-y = 6-10 = -4
y = 4
Substitute with the y in equation II to get x as follows:
2x = 5 - 2y
2x = 5 - 2(4)
2x = 5 - 8 = -3
x = -3/2
From the above calculations:
x = -3/2
y = 4
Answer:
The required probability is 0.533.
Step-by-step explanation:
Consider the provided information.
The actual weight of the chocolate has a uniform distribution ranging from 31 to 32.5 ounces.
Let x is the random variable for the actual weight of chocolate.
According to PDF function.
Where
It is given that ranging from 31 to 32.5 ounces.
Substitute a=31 and b=32.5 in above function.
We need to find the probability that a box weighs less than 31.8 ounces
Now according to PDF:
Hence, the required probability is 0.533.
Answer:
B. 60.26°
Step-by-step explanation:
Given:
Consider the diagram representing the above scenario.
The top of the house where dad is standing is at A. The point where his son is standing is B. The bottom of the house is at C. AC is the height of house, BC is the distance between the house and son.
Height of the house (AC) = 21 ft
Distance between the house and son (BC) = 12 ft
Let the angle of depression for the dad be 'x'.
From the figure, it is clear that,
Angle of depression of the dad will be same as angle of elevation of Artie.
For triangle ABC,
Therefore, the angle of depression from the top of the house to the spot where Artie is standing is 60.26°.
Therefore, the correct option is option (B).
Answer: c = 3
Step-by-step explanation: Distribute 0.2 to (10-5c)
2-1c=5c-16
Then subtract 2 on both sides and subtract the 5c.
-1c=5c-18
-6c=-18
Then divide -6 to -18
-18/-6 = 3
V cylinder = A_base * height, A_base = pi*r^2, if height=radius+7, then
V = pi*r^2(r+7)
That's it