a car initially at rest move with the constant accerates along straght line read after it's spread increase and finally related
1 answer:
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The distance covered by the object between t =4 s and t = 6 s is 4 m
Explanation:
In a velocity-time graph, the distance covered by the object represented can be found by calculating the area under the curve.
Therefore, the distance covered by the object between t = 4 s and t = 6 s is the area under the curve between 4 s and 6 s.
We see that we have to calculate the area of a triangle, with:
Base:
And height:
Therefore, the area is
So, the distance covered by the object is 4 m.
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Answer:
The speed in the smaller section is
Explanation:
Assuming all the parts of the pipe are at the same height, we can use continuity equation for incompressible fluids:
(1)
With Q the flux of water that is with A the cross section area and v the velocity, so by (1):
subscript 2 is for the smaller section and 1 for the larger section, solving for :
(2)
The cross section areas of the pipe are:
but the problem states that the diameter decreases 86% so , using this on (2):