Jim is ranked third best in his class of 50 students.
Answer:
-6xy
Step-by-step explanation:
(2x-y)x(x-2y)-(x+2y)X(2x-y)
remove the parentheses
2x^2-4xy+xy-2y^2-(2x^2-xy+4xy-2y^2)
collect terms
2x^2-4xy+xy-2y^2-(2x^2+3xy-2y^2)
remove the parentheses
2x^2-4xy+xy-2y^2-2x^2-3xy+2y^2
remove the opposites, collect the terms to get -6xy
Answer: The average distance the ambulance travels to reach an emergency situation is 6.64 miles.
Step-by-step explanation:
Hi, to answer this question we have to apply the speed formula:
Speed rate = distance / time
Replacing with the values given:
0.83 miles per minute = d / 8 minutes
Solving for d (distance)
0.83 mpm x 8 m =d
d =6.64 miles
The average distance the ambulance travels to reach an emergency situation is 6.64 miles.
Feel free to ask for more if needed or if you did not understand something.
25+80=105
180-105=75=a
y=90 because it’s a right triangle so
25+90=115
180-115=65=x
y=90
x=65
a=75