From the top of a 100 ft air traffic control tower, an airplane is observed flying in at an angle of 32\displaystyle \degree°. I
f the airplane is 3000 feet away, what is the plane's altitude?
1 answer:
Answer:
1974.6 feets
Step-by-step explanation:
The plane's altitude is : h + 100 feets
To obtain h, according to the attached picture ;
We can use trigonometry :
Tan θ = opposite / Adjacent
Opposite = h ; adjacent = 3000 feets
Tan 32° = h / 3000
h = 3000 * 0.6248693
h = 1874.6080
Plane's altitude :
h + 100 feets
(1874.6080 + 100) feets
= 1974.6 feets
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