Third choice is correct hope I helped:3
Answer:
Number of 12$ Shares? 25
Number of 14$ Shares? 57
Step-by-step explanation:
Let x = number of $12 shares.
Let y = number of $14 shares.
"Ivan has $1098 worth of $12 and $14 stock shares."
12x + 14y = 1098
The number of $14 shares is seven more than twice the number of $12 shares.
y = 2x + 7
We have a system of equations.
12x + 14y = 1098
y = 2x + 7
We can use the substitution method since the second equation is already solved for y. Substitute 2x + 7 for y in the first equation.
12x + 14(2x + 7) = 1098
12x + 28x + 98 = 1098
40x = 1000
x = 25
There are 25 $12 shares.
y = 2x + 7 = 2(25) + 7 = 57
There are 57 $14 shares.
Check:
25 × $12 + 57 × $1`4 = $300 + $798 = $1098
The total value is correct, so the answer is correct.
Answer:
3<5
Step-by-step explanation: dont see a picture but i have an example
Answer:
The second time when Luiza reaches a height of 1.2 m = 2 08 s
Step-by-step explanation:
Complete Question
Luiza is jumping on a trampoline. Ht models her distance above the ground (in m) t seconds after she starts jumping. Here, the angle is entered in radians.
H(t) = -0.6 cos (2pi/2.5)t + 1.5.
What is the second time when Luiza reaches a height of 1.2 m? Round your final answer to the nearest hundredth of a second.
Solution
Luiza is jumping on trampolines and her height above the levelled ground at any time, t, is given as
H(t) = -0.6cos(2π/2.5)t + 1.5
What is t when H = 1.2 m
1.2 = -0.6cos(2π/2.5)t + 1.5
0.6cos(2π/2.5)t = 1.2 - 1.5 = -0.3
Cos (2π/2.5)t = (0.3/0.6) = 0.5
Note that in radians,
Cos (π/3) = 0.5
This is the first time, the second time that cos θ = 0.5 is in the fourth quadrant,
Cos (5π/3) = 0.5
So,
Cos (2π/2.5)t = Cos (5π/3)
(2π/2.5)t = (5π/3)
(2/2.5) × t = (5/3)
t = (5/3) × (2.5/2) = 2.0833333 = 2.08 s to the neareast hundredth of a second.
Hope this Helps!!!
Answer:
x≥5
Step-by-step explanation:
-1 ≥ x/-5
x/-5 ≤ -1
x(-1)/5 ≥ (-1) (-1)
x/5 ≥ 1
5x/5 ≥ 1 ×5
x ≥ 5
I'm not sure but I tried.
For the graph: you can draw a line about 15cm, put 0 at the start then after 5cm put 5 then 10 at 10cm and 15 at the end. At 5 put • that's the starting and go all the way to 15 and add > to show that the line continues. I'm not good at explaining but I hope it helps.
