Answer:
3) (2,-9)
4) (0,-5)
5) (1,-8)
Step-by-step explanation:
3)
The vertex will occur between you x-intercepts.
You already found that happens at x=2.
To find the corresponding y-coordinate, replace x in
f(x)=(x+1)(x-5) with 2:
f(2)=(2+1)(2-5)
f(2)=(3)(-3)
f(2)=-9
So the vertex is (2,-9).
4)
The y-intercept is when x=0.
So in f(x)=(x+1)(x-5) replace x with 0:
f(0)=(0+1)(0-5)
f(0)=(1)(-5)
f(0)=-5
So the y-intercept is (0,-5).
5)
To find another point just plug in anything besides any x already used.
We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.
So replace x in f(x)=(x+1)(x-5) with x=1:
f(1)=(1+1)(1-5)
f(1)=(2)(-4)
f(1)=-8
So another point to graph is (1,-8).
ABC and HJK are congruent and the corresponding sides and angles are equal. Side HJ is congruent with side AB so HJ is also 3.5cm in length.
The outside angle of B needs to equal 180 - 79 = 101 degrees.
The 3 outside angles of a triangle need to equal 360 degrees.
Set up the equation with what we know:
X + (x+5) + 101 = 360
Simplify:
2x + 106 = 360
Subtract 106 from both sides:
2x = 254
Divide both sides by 2:
x = 254 / 2
x = 127