Answer:
I don't do physics , I'm sorry can't help you
Answer:
I = 2172.46 A
Explanation:
Given that,
The length of a solenoid, l = 2.1 m
The inner radius of the solenoid, r = 28 cm = 0.28 m
The number of turns in the wire, N = 1000
The magnetic field in the solenoid, B = 1.3 T
We need to find the current carried by it. We know that, the magnetic field in a solenoid is given by :
Put all the values,
So, it carry current of 2172.46 A.
Igneous rock your welcome
Current will be
now just pluf in the values and Voila..