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2 years ago

Order the following from smallest to largest. Place the smallest value at the top of your list.

Chemistry

2 answers:

Basile [38]2 years ago

8 0

10kg
100g
1,000,000mg
Is the answer

BlackZzzverrR [31]2 years ago

5 0

Answer:

100g
1.000.000mg
10 kg

Explanation:

1.000.000mg = 1,000 g =1kg

100g =.01kg

10 kg

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16. Formaldhyde has a mole ratio of 1 mole C: 2 moles H: 1 mole O. Its empirical formula is the same as its

Dominik [7]

Answer:

d. 97.60 g

Explanation:

Given parameters:

Number of moles of formaldehyde = 3.25moles

Ratio:

C H O

1 2 1

Unknown:

Mass of this sample = ?

Solution:

The empirical formula of a compound is its simplest formula. It is the simplest whole number ratio of the atoms in a given substance.

The molecular formula is the actual formula of the compound.

Since the molecular and empirical formula are the same here, the formula of the compound is;

CH₂O

To find the mass of the formaldehyde, use the expression below;

Mass = number of moles x molar mass

molar mass of CH₂O = 12 + 2(1) + 16 = 30g/mol

Mass = 3.25 x 30 = 97.5g

6 0

2 years ago

Many home barbeques are fueled with propane gas (C3H8)(C3H8). Part A What mass of carbon dioxide is produced upon the complete c

Andrew [12]

Answer:

41264 g of CO₂

Explanation:

Combustion reaction is:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

1 mol of propane react to 5 moles of oxygen in order to proudce 3 moles of carbon dioxide and 4 moles of water.

In a combustion reaction, our reactant reacts to oxygen and the products are always CO₂ and water.

We have the volume of propane but we need moles of it, so we need to apply density.

Density = mass / volume so mass = density . volume.

Density of propane is: 493 g/L

Mass of propane is 493 g/L . 27.9L = 13754.7 g

We convert mass to moles: 13754.7 g . 1 mol/ 44g = 312.6 moles

According to reaction, 1 mol of propane can produce 3 moles of CO₂

Our 312.6 moles will produce 312.6 . 3 = 937.8 moles

We convert moles to mass: 937.8 mol . 44 g/mol = 41264 g

3 0

2 years ago

Which of the following affects the weight of a person on earth

kobusy [5.1K]

I think it may be gravity. Are there answer choices??

5 0

2 years ago

Calculate the amount of heat energy in KJ required to convert 45.0 g of ice at -15.5'C to steam at 124.0°C. (Cwater 118 Jig'c, G

dangina [55]

Answer : The enthalpy change or heat required is, 139.28775 KJ

Solution :

The conversions involved in this process are :

$(1):H_2O(s)(-15.5^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(124^oC)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change or heat required = ?

m = mass of water = 45 g

$c_{p,s}$ = specific heat of solid water = $2.09J/g^oC$

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$c_{p,g}$ = specific heat of liquid water = $1.84J/g^oC$

n = number of moles of water = $\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{45g}{18g/mole}=2.5mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

$\Delta H_{vap}$ = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[45g\times 4.18J/gK\times (0-(-15.5))^oC]+2.5mole\times 6010J/mole+[45g\times 2.09J/gK\times (100-0)^oC]+2.5mole\times 40670J/mole+[45g\times 1.84J/gK\times (124-100)^oC]$

$\Delta H=139287.75J=139.28775KJ$ (1 KJ = 1000 J)

Therefore, the enthalpy change is, 139.28775 KJ

3 0

2 years ago

Why are alloys generally used to make everyday objects

mestny [16]

Because alloys are two or more metals mixed into one metal which makes all of the properties of these metals better and stronger.

6 0

2 years ago