The relationship between independent and dependent variables is constant. The independent variables are not affected and do not change while dependent variables rely on something or a particular change.
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Answer:
A planet's <u>hydrosphere</u> can be<u> liquid</u>, <u>vapor</u>, or <u>ice</u>. On Earth, in the places at the <u>north and south pole</u>, water exists in ice or glacier form, in the <u>atmosphere</u> it exists in vapor form and liquid water exists on the <u>surface</u> in the form of oceans, lakes and rivers. It also exists below ground as <u>groundwater</u>, in wells and aquifers. Water collects in clouds, then falls to Earth in the form of <u>rain or snow</u>,
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Answer: The concentration of ions in the resulting solution is 1.16 M.
Explanation:
To calculate the molarity of the solution after mixing 2 solutions, we use the equation:
where,
are the n-factor, molarity and volume of the
are the n-factor, molarity and volume of the
We are given:
Putting all the values in above equation, we get
The concentration of ions in the resulting solution will be same as the molarity of solution which is 1.16 M.
Hence, the concentration of ions in the resulting solution is 1.16 M.
Answer:
-0.1767°C (Option A)
Explanation:
Let's apply the colligative property of freezing point depression.
ΔT = Kf . m. i
i = Van't Hoff factot (number of ions dissolved). Glucose is non electrolytic so i = 1
m = molality (mol of solute / 1kg of solvent)
We have this data → 0.095 m
Kf is the freezing-point-depression constantm 1.86 °C/m, for water
ΔT = T° frezzing pure solvent - T° freezing solution
(0° - T° freezing solution) = 1.86 °C/m . 0.095 m . 1
T° freezing solution = - 1.86 °C/m . 0.095 m . 1 → -0.1767°C
Answer:
56°
Explanation:
First calculate
The interplanar spacing can be calculated from:
The diffraction angle is determined from:
Solve for
The diffraction angle is: