Answer: C) 133
Step-by-step explanation:
The formula to find the sample size is given by :-
, where z* = Critical z-value
= Population standard deviation for prior study.
E= Margin of error.
As per given , we have
E= 5
The critical z-value for 90% confidence level is 1.645.
Substitute al;l the value sin the above formula , we get
Hence, the minimum sample size needed is 133.
Thus , the correct answer is : C) 133
Answer:
m = -1/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
9m - m + 3 = -2(m + 1)
<u>Step 2: Solve for </u><em><u>m</u></em>
- Combine like terms: 8m + 3 = -2(m + 1)
- Distribute -2: 8m + 3 = -2m - 2
- Add 2m on both sides: 10m + 3 = -2
- Isolate <em>m</em> term: 10m = -5
- Isolate <em>m</em>: m = -1/2
If you want it in mixed number form it is
8 1/30
Decimal form is
8.03
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.
∴N(c₁) =
N(c₂) =
∴N(c₁c₂) =
∴ Number of positive integers that are not divisible by 4 or 6,
N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4