Answer:
The minimum score required for an interview is 77.252
Step-by-step explanation:
We solve this using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
Top 15% of the candidates is a ranking that is equivalent to = 100 - 15% = 85th percentile.
The z score of 85th percentile = 1.036
Mean = 70
Standard Deviation = 7
Minimum score = raw score = ???
Hence:
1.036 = x - 70/7
Cross Multiply
1.036 × 7 = x - 70
7.252 = x - 70
x = 70 + 7.252
x = 77.252
The minimum score required for an interview is 77.252
a - b ≤ 25
b - yes
c - 26 ( draw the picture for your explanation)
Answer:
690
Step-by-step explanation:
Round from the tens place.
27 is the answer, I can explain how I got that if you need.
