The distance between Dustin and the planet is larger than the distance between Barb and the planet
Explanation:
The magnitude of the gravitational force between each astronaut and the planet is given by
where
:
is the gravitational constant
M is the mass of the planet
m is the mass of the astronaut
r is the separation between the astronaut and the planet
In this problem, we have:
- The force of gravity between Dustin and the planet is 120,265 N
- The force of gravity between Barb and the planet is 354,999 N
We see that the force exerted by the Planet on Barb is much greater than the force exerted by the planet on Dustin. Assuming that the mass of Dustin and Barb is similar, then we can say that the magnitude of the force of gravity depends mainly on the distance:
And since the force is inversely proportional to the square of the distance, this means that the distance between Dustin and the planet is larger than the distance between Barb and the planet.
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Answer:
3100 m/s
Explanation:
The relationship between frequency and wavelength of a wave is given by the wave equation:
where
v is the speed of the wave
f is its frequency
is the wavelength
For the wave in this problem,
f = 15,500 Hz
Therefore, the wave speed is
Her magnitude of deceleration on the ice would be 15.126m/s
Answer:
Explanation:
For sound level in decibel scale the relation is
dB = 10 log I / I₀ where I₀ = 10⁻¹² and I is intensity of sound whose decibel scale is to be calculated .
Putting the given values
61 = 10 log I / 10⁻¹²
log I / 10⁻¹² = 6.1
I = 10⁻¹² x 10⁶°¹
intensity of sound of 5 persons
= 10log 5 x 10⁶°¹
= 10( 6.1 + log 5 )
= 67.98
sound level will be 67.98 dB .
Answer:
Keeping the speed fixed and decreasing the radius by a factor of 4
Explanation:
A ball is whirled on the end of a string in a horizontal circle of radius R at constant speed v. The centripetal acceleration is given by :
We need to find how the "centripetal acceleration of the ball can be increased by a factor of 4"
It can be done by keeping the speed fixed and decreasing the radius by a factor of 4 such that,
R' = R/4
New centripetal acceleration will be,
So, the centripetal acceleration of the ball can be increased by a factor of 4.
