The area of the square increasing at 30
The rate of change function is defined as the rate at which one quantity is changing with respect to another quantity. In simple terms, in the rate of change, the amount of change in one item is divided by the corresponding amount of change in another
Let the side of a square be x.
So,
Area of square =
A =
Differentiating with respect to time we get,
dA/dt = 2x dx/dt
When area = 9 the side becomes 3 cm
At x = 3cm and dx/dt = 5 cm/s (Given)
dA/dt = 2.3.5 = 30
Thus the area of the square increasing at 30
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24.6-17= 7.6 (km) i think so
Remember the rules of Sohcahtoa (Sine, cosine, tangent). For this problem we take the cosine of 38 because the labeled sides are the adjacent leg and the hypotenuse.
Cos(38)=79/x
Cosine of 38 is about 0.7880
0.7880=79/x
Next we multiply both sides by the denominator
(x) 0.7880=79 (x)
Then divide.
<u>0.7880x</u>= <u>79</u>
0.7880 0.7880
X=100.25
Hope this helped :)
Two equations
let c the calories in carrot
let h the <span>calories in </span><span>hershey's kisses
</span><span>
4c + 8h = 230 eq 1</span>
10 c + 7 h = 263 eq 2
to solve the solution we multiply eq 1 by 10
we multiply <span>eq 2 by 4
</span>
40 c + 80 h = 2300
40c + 28 h = 1052
we subtract the two equations we get
52 h = 1248
h= 24
and so in replacing h = 24 in the equation we get c = 9.5