The measure of the unknown angle are; a) x = 89 degrees, b) p = 92 degrees.
<h3>What is the sum of all the angles of a regular polygon?</h3>
For a regular polygon of any number of sides, the sum of its exterior angle is 360°.
We already know that a 4-sided polygon's angles add up to 360 degrees.
So to find the value of x:
69 + 118 + 84 + x = 360
x = 360 - (69 + 118 + 84)
x = 89 degrees
b)
For a 4-sided polygon, we also know that the outside angles add up to 360 degrees.
So to find the value of p:
100 + 62 + 106 + p = 360
p = 360 - (100 + 62 + 106)
p = 92 degrees
Learn more about interior angles of a regular polygon here:
brainly.com/question/14173422
#SPJ1
an = a1+ d(n-1)
a1 =14
an=206 when n=25
206 = 14 + d (25-1)
206 = 14 + d * 24
subtract 14 from each side
192 = 24d
divide by 24 on each side
d=8
The common difference is 8
It goes into it 0 times but what you can do is 11 going into 12 which would give you 1.1 instead of you making it a remainder. <span />
Answer:
You dont need to
Step-by-step explanation:
A hypothesis is just a guess, so you cant be wrong
Okay ShallBeTheLast, what we will do will involve a lot of simple plug and play kind of actions.
To start we must notice one number must be negative and the other should be positive, because the multiplied number is a negative.
Next, lets multiply number that have a sum of 10 (keep in mind one has to be negative and the other has to be positive).
-1 * 10 = -10 false
-2 * 12 = -24 false
-3 * 13 = -39 false
notice that no number working and it's only getting farther away.
There is no solution for this that involves to integers.
I think you might of wrote the question backwards.
If that is the case we would run numbers like.....
-1 * (-6) = 7 false
-2 * (-5) = 10 true!!!!
-2 and -5 would work