Answer:
Mass = 153.48 g
Explanation:
Given data:
Volume of solution = 2.50 L
Molarity = 0.48 M
Mass required = ?
Solution:
Molarity = number of moles / volume in litter
Number of moles = Molarity × volume in litter
Number of moles = 0.48 M × 2.50 L
Number of moles = 1.2 mol
Mass of HI:
Number of moles = mass/molar mass
Mass = Number of moles × molar mass
Mass = 1.2 mol × 127.9 g/mol
Mass = 153.48 g
It would be carbon dioxide codd2 for the molecules
Move more freely :) hope this helps!
A. Carbon monoxide
b. Phosphorous trichloride
c.
d.nitrogen
e. Water- Hydrogen - Oxygen
f.
