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3 years ago

A 1970 comic book has appreciated 7% per year and originally sold for $0.35. What will the comic book be worth in 2017?

1 answer:

6 0

You tell me if this makes sense to you.

It's 47 years from 1970 to 2017 so you would need to multiply 7% by the 47 years.

So: 0.07x47= 3.29

Now you should add your new price to your original price: $3.29+$0.35= 3.64

So it should cost $3.64 now. Yes that does seem kind of low but that's how you do it.

I hope this helps :)

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2x-56=34

inessss [21]

Answer:

x=45

Step-by-step explanation:

2x-56=34

Add 56 to both sides

2x-56+56=34+56

Simplify;

2x=90

Divide both sides by 2

2x/2=90/2

Simplify;

x=45

7 0

2 years ago

Read 2 more answers

Simplify this expression: -2x + 3 – (5 – 6x). Can someone pls explain how to do this dont just give the awnser

Verizon [17]

Answer:

-2x + 3 – (5 – 6x) = 4x - 2

Step-by-step explanation:

The given expression is :

-2x + 3 – (5 – 6x)

We need to simplify the above expression. First opening the brackets.

-2x + 3 – (5 – 6x) = -2x + 3 – 5 + 6x

Taking like terms together,

= -2x+6x + 3 -5

= 4x - 2

So, the simplified expression is 4x - 2.

5 0

2 years ago

you have $18 to buy peppers. peppers cost $1.50 each. write and solve an inequality that represents the number of peppers you ca

Nezavi [6.7K]

At most 12 peppers can be bought with $18

Step-by-step explanation:

Given

Total amount for peppers = $18

Cost per pepper = $1.50

Let p be the number of peppers that can be bought from $18 at $1.50 per pepper

So,

$1.50p\leq 18$

Dividing both sides by 1.50

$\frac{1.50p}{1.50}\leq \frac{18}{1.50}\\p\leq 12$

Hence,

At most 12 peppers can be bought with $18

Keywords: Inequality, solution

Learn more about inequalities at:

#LearnwithBrainly

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

<u>Given expression is </u>

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

<u>Hence, </u>

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago

What is the sum of the first 20 terms of the arithmetic sequence shown? \displaystyle \frac{1}{3} 3 1 , \displaystyle \frac{2}

Murrr4er [49]

Answer:

Step-by-step explanation:

$a_1$ = First term = $\dfrac{1}{3}$

$d$ = Common difference = $\dfrac{2}{3}-\dfrac{1}{3}=\dfrac{1}{3}$

$n$ = Number of terms = 20

Sum of arithmetic progression is given by

$S=\dfrac{n}{2}[2a_1+(n-1)d]\\\Rightarrow S=\dfrac{20}{2}\times (2\times \dfrac{1}{3}+(20-1)\dfrac{1}{3})\\\Rightarrow S=70$

The sum of the first 20 terms of the arithmetic sequence is 70.

5 0

2 years ago