Step-by-step explanation:
tan⁻¹(x) = ∑ₙ₌₀°° (-1)ⁿ x²ⁿ⁺¹ / (2n+1)
tan⁻¹(1/√3) = ∑ₙ₌₀°° (-1)ⁿ (1/√3)²ⁿ⁺¹ / (2n+1)
tan⁻¹(1/√3) = ∑ₙ₌₀°° (-1)ⁿ (1/√3) (1/√3)²ⁿ / (2n+1)
tan⁻¹(1/√3) = (1/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)
π/6 = (1/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)
π = (6/√3) ∑ₙ₌₀°° (-1)ⁿ (1/3)ⁿ / (2n+1)
π = 2√3 ∑ₙ₌₀°° (-1)ⁿ / (3ⁿ (2n+1))
Let and . Then
and
The expression under the square root can be rewritten as
Recall that
so that
and assuming and , we end up with
so that
as required.
Answer:
The value of x = 12, makes the statement true
Option D is correct option.
Step-by-step explanation:
What value of x makes this statement true?
We need to solve the equation to find value of x
Subtract 2x on both sides
So, the value of x is: x=12
So, The value of x = 12, makes the statement true
Option D is correct option.
Answer:
x = 5 or x = 1
Step-by-step explanation:
x² - 6x + 7 = 0
x² - 6x = -7
x² - 6x + 9 = -7 + 9 1/2 of the x term than square it and add it the both sides.
(x - 3)(x - 3) = 2
( x -3)² = 2
=
(x - 3) = ± 2
x - 3 = 2 or x - 3 = -2
x = 5 or x = 1
Without the table I will guess 5 is common to all 3 they are proportional