Answer:
The length of AA' = √29 = 5.39
Step-by-step explanation:
* Lets revise how to find the length of a line joining between
any two points in the coordinates system
- If point A is (x1 , y1) and point B is (x2 , y2)
- The length of AB segment √[(x2 - x1)² + (y2 - y1)²]
* Lets use this rule to solve the problem
∵ Point A is (0 , 0)
∵ Point A' = (5 , 2)
∵ (x2 - x1)² = (5 - 0)² = 5² = 25
∵ (y2 - y1)² = (2 - 0)² = 2² = 4
∴ The length of AA' = √(25 + 4) = √29 = 5.39
Hello!
Answer:
1) 7k+35
2) 9n−36
3) 4x+22
Step-by-step explanation:
1) 7(k+5)
1) 7k+7×5
1) 7k+35
2) 9(n-4)
2) 9n+9×−4
2) 9n−36
3) 4(x+5)+2
3) 4x+20+2
3) 4x+(20+2)
3) 4x+22
Hope this helps!
Answer:
24.61%
Step-by-step explanation:
The distance covered in first week = 195 miles
The distance covered in the second week = 243 miles
We need to find the percentage increase in distance. It can be calculated as follows :
So, the increase in distance is equal to 24.61%.
This is the concept of relative speed; We are required to calculate the speed of the car and the bicycle.
Distance between the car and Bicycle=374 miles
Time they met=5.5 hr
Speed traveled by bicycle=x
Speed traveled by car=x+33.4334
Relative speed=x+(x+33.4334)=(2x+33.4334) mph
Distance=speed*time
374=(2x+33.4334)*5.5
374=11x+183.8837
collecting like term we get:
374-183.8837=11x
11x=190.1163
thus;
x=(190.1163)/(11)
x=17.2833 mph
thus the speed of the bicycle was x=17.2833 mph
The speed of the car was (x+33.4334)=(17.2833+33.4334)=50.7167 mph
Answer:
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Angle a = 126. What is the measure of angle b? Explain how you calculated your answer.
Angle a = 126 Write an equation(s) in terms of b to find the measure of angle h.
Calculate the measure of angle h, using the equation(s) you wrote for Part B.
How would knowing the measure of angle y change the equation(s) you wrote in Part B to find the measure of angle h?
2021 Muminate Education Inc Your input: factor x2+4x+3.
To factor the quadratic function x2+4x+3, we should solve the corresponding quadratic equation x2+4x+3=0.
Indeed, if x1 and x2 are the roots of the quadratic equation ax2+bx+c=0, then ax2+bx+c=a(x−x1)(x−x2).
Solve the quadratic equation x2+4x+3=0.
The roots are x1=−1, x2=−3 (use the quadratic equation calculator to see the steps).
Therefore, x2+4x+3=1(x+1)(x+3).
(x2+4x+3)=1(x+1)(x+3)
Step-by-step explanation:
