Answer:
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what is the question?
Answer:
Step-by-step explanation:
You would first have to plug in for x, (which is already given). After plugging in for x, you would need to solve the equation to get y.
Once you have both x and y, you will have your (x,y)
For example: (given x value = -5)
so:
x = -5
y = -14
( -5, -14)
Answer:
C
Step-by-step explanation:
Answer: The correct option is
(D) 60.
Step-by-step explanation: Given that the number of stamps that Kaye and Alberto had were in the ration of 5:3 respectively.
After Kaye gave Alberto 10 of her stamps, the ration of the number of Kaye had to the number of Alberto had was 7:5.
We are to find the number of stamps that Kaye had more than Alberto.
Let the number of stamps Kaye and Alberto has are 5x and 3x respectively.
Then, according to the given information, we have
So, the number of stamps that Kaye had = 5 × 30 = 150
and
the number of stamps that Alberto had = 3 × 30 = 90.
Therefore, the number of stamps that Kaye had more than Alberto is
Thus, Kaye had 60 stamps more than Alberto.
Option (D) is CORRECT.
Answer and Step-by-step explanation:
C(x) be the statement "x has a cat"
D(x) be the statement "x has a dog"
F(x) be the statement "x has a ferret".
Universe = x = all students in your class.
a) A student in your class has a cat, a dog and a ferret
= ∃x(C(x) ∧ D(x) ∧ F(x))
b) All students in your class have a cat, a dog, or a ferret = ∀x(C(x) ∨ D(x) ∨ F(x))
c) Some students in your class has a cat and a ferret but not a dog = ∃x (C(x) ∧ F(x) ∧ ¬D(x))
d) No student in this class has a cat, a dog and a ferret ¬∃x (C(x) ∧ D(x) ∧ F(x))
e) For each of the three animals, cats, dogs and ferrets, there is as student in your class who has one of the three animals. (∃xC(x)) ∧ (∃xD(x)) ∧ (∃xF(x))