2 years ago

HelPPP I need ANSWERS DUEE TOMORROW

Mathematics

1 answer:

aleksley [76]2 years ago

3 0

7. 233
8. 4
9. 6
10. 5
11. 4
12. 7
13. 7

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Help me please emergency

adoni [48]

Step-by-step explanation:

this can be found by determination of the highest and lowest x values

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1 year ago

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A football team of 11 players has a mean height of 1.83m. One player is injured and is replaced by a player of height 1.85m. The

trapecia [35]

Answer:

As the average has increased the height of the new player must be more then the height of the player which was injured.

The difference between the previous average and the new average is 0.01 m.

Therefore the average is increased by 0.01 m.

Therefore the total height of all the players is increased by 0.01*11=0.11 m

Therefore as the increase in the total height is made by the player with height 1.85 m,the height of the player who was injured is 1.85–0.11=1.74 m

The height of the player who was injured is 1.74 m

Step-by-step explanation:

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1 year ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

tensa zangetsu [6.8K]

Answer:

$y=3t^9+C$

Step-by-step explanation:

Given: $\dfrac{dy}{dt}=27t^8$

We want to obtain the general solution of the given differential equation.

$dy=27t^8$ dt\\$Take the integral of both sides\\\int dy =\int 27t^8$ dt$\\y=\dfrac{27t^{8+1}}{8+1} +C$, (where C is the constant of integration)$\\y=\dfrac{27t^{9}}{9} +C\\\\y=3t^9+C$

The general solution of the differential equation is: $y=3t^9+C$

CHECK:

$\dfrac{d}{dt} y=\dfrac{d}{dt}(3t^9+C)=\dfrac{d}{dt}(3t^9)+\dfrac{d}{dt}(C)\\\\\text{Since derivative of a constant is zero}\\\\\dfrac{dy}{dt}=27t^{9-1}\\\dfrac{dy}{dt}=27t^8$