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2 years ago

Find the erea of the trapezoid.

Mathematics

1 answer:

katrin2010 [14]2 years ago

6 0

9514 1404 393

Answer:

32 yd²

Step-by-step explanation:

Use the area formula with the given dimensions.

A = 1/2(b1 +b2)h . . . . . base lengths b1, b2; height h

A = 1/2(2 +6)8 = 1/2(8)(8) = 32 . . . . square yards

The area of the trapezoid is 32 square yards.

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PLEASE HELP AND PLEASE SHOW YOUR WORKING

professor190 [17]

Answer:

S = 13 - x

T = (18 + x) / 2

Step-by-step explanation:

S = 18

T= 18

Sue gives away x, so subtract it from 18. But Tony gets x, so add it to 18 in his expression.

S = 18 - x

T= 18 + x

Sue eats 5 so subtract 5 from her expression. Tony eats half, so divide his expression by 2.

S = 18 - x - 5

T = 18 + x / 2

Simplify 18-5.

S = 13 - x

T = (18 + x) / 2

6 0

2 years ago

.solve for c c−1.5+6.8=0.6 I NEED HELP

kiruha [24]

Answer: c= -4.7

Step-by-step explanation:

Look at link hope it helps

4 0

2 years ago

What's the answer????

Blizzard [7]

Answer:

Range: (2, 14)

General Formulas and Concepts:

Algebra I

Range is the set of y-values that are outputted by function f(x)

Step-by-step explanation:

According to the graph, our line's y-values span from 2 to 14. Since both 2 and 14 are open dot, they are exclusive from the range:

Interval Notation: (2, 14)

Inequality Notation: 2 < y < 14

5 0

2 years ago

Assume that a policyholder is four times more likely to file exactly two claims as to file exactly three claims. Assume also tha

kykrilka [37]

Answer:

1.3125

Step-by-step explanation:

Given that our random variable $X$ follows a Poisson distribution $P(X=k)=\frac{\lambda^k e^-^p}{k!} \ \ \ \ \ \ \ \ p=\lambda$

Evaluate the formula at $k=2,3:$

$P(X=2)=0.5\lambda^2e^{-\lambda}\\\\P(X=3)=\frac{1}{6}\lambda^2e^{-\lambda}$

#since

$4P(X=2)=P(X=3);\\\\0.5\lambda^2e^{-\lambda}=4\times\frac{1}{6}\lambda^3e^{-\lambda}\\\\0.5\lambda^2=\frac{2}{3}\lambda^3\\\\0.75=\lambda$

The mean and variance of the Poisson distributed random variable is equal to $\lambda$ :

$\mu=\lambda=0.75\\\sigma ^2=\lambda=0.75$

#By property variance:

$\sigma ^2=V(X)=E(X^2)-(E(X))^2=E(X^2)\\\\E(X^2)=\sigma^2+\mu^2=0.75+0.75^2=1.3125$

The expectation is 1.3125

4 0

2 years ago

Number of subsets of B={p,q,r}

oksian1 [2.3K]

Answer:

Step-by-step explanation:

B = {p , q , r}

Number of subsets = $2^{n}$

Her, n is the number of elements in the set.

Number of subsets = 2³ = 8

3 0

2 years ago