The domain is the limits of the function. Since time doesnt go negative, start with 0. At time 0, the height is
-16(0)^2 + 144 = 144ft
Then, solve for t to find the upper limit for t, which is when the height is zero (since you're dropping the object).
-16t^2 + 144 = 0
-16t^2 = -144
t^2 = 9
t = sqrt(9)
t = 3
The domain is 0 to 3 seconds.
Expand and simplify
(x-3) (x-3) +2(x-3) -8=0
(x-3+2)(x-3)-8=0
(x-1)(x-3)-8=0
x^2 -4x +3-8=0
x^2 - 4x -5=0
x^2 -5x +x-5=0
x(x-5)+x-5=0
(x+1)(x-5)=0
x= - 1, 5
9514 1404 393
Answer:
-3/4, 3
Step-by-step explanation:
The zeros are the values of x that make h(x)=0. Those are the values of x that make the factors of h(x) be zero.
-4x -3 = 0 ⇒ x = -3/4
x -3 = 0 ⇒ x = 3
The zeros of the function are -3/4 and 3.
Answer:
1 ) y = 2x - 1
slope = 2
y intercept is (0,-1)
2) y = -1/2x + 5
slope = -0.5
y intercept = (0,5)
Step-by-step explanation:
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...