Zero order are reactions in which concentration of reactant has NO effect on RATE OF REACTION.
2. First order are reactions in which concentration of one reactant is proportionate to the RATE OF REACTION.
Exp: That means when you increase the concentration of the one reactant, then the rate of reaction will increase by the same degree of extent.
3. Second order are reactions in which concentration of two reactant has an effect on the RATE OF REACTION.
Formula:
1. Zero order Rate = k
2. First order Rate = k(A)^m
3. Second order Rate = k(A)^m(B)^n
where () represents concentration
and equation is mA + nB -> Product.
Answer:
V₂ → 106.6 mL
Explanation:
We apply the Ideal Gases Law to solve the problem. For the two situations:
P . V = n . R . T
Moles are still the same so → P. V / R. T = n
As R is a constant, the formula to solve this is: P . V / T
P₁ . V₁ / T₁ = P₂ .V₂ / T₂ Let's replace data:
(1.20 atm . 73mL) / 112°C = (0.55 atm . V₂) / 75°C
((87.6 mL.atm) / 112°C) . 75°C = 0.55 atm . V₂
58.66 mL.atm = 0.55 atm . V₂
58.66 mL.atm / 0.55 atm = V₂ → 106.6 mL
Answer:
704.6 g CO2
Explanation:
MM sucrose = 342.3 g/mol
MM CO2 = 44.01 g/mol
g CO2 = 456.7 g sucrose x (1 mol sucrose/MM sucrose) x (12 moles CO2/1 mol sucrose) x (MM CO2/1mol CO2) = 704.6 g CO2
The first option Forsure .