2 years ago

Solve quadratic inequality x^2+4x≥0

Mathematics

1 answer:

klemol [59]2 years ago

7 0

Answer:

Step-by-step explanation:

y = x² + 4x is an up-opening parabola with x-intercepts 0 and -4.

y ≥ 0 when x≤-4 or x≥0

range: (-∞,-4)∪[0,+∞)

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The mean absolute deviation is: 7.44

Step-by-step explanation:

Given

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Required

The mean absolute deviation

First, calculate the mean

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$\bar x = \frac{98+78+84+75+91}{5}$

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So, we have:

$M = \frac{1}{5}(|98 - 85.2|+|78 - 85.2|+|84 - 85.2|+|75 - 85.2|+|91 - 85.2|)$

$M = \frac{1}{5}(|12.8|+|-7.2|+|-1.2|+|-10.2|+|5.8|)$

Remove absolute brackets

$M = \frac{1}{5}(12.8+7.2+1.2+10.2+5.8)$

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