Answer:
delta r(x) = (delta (r)) * cos(alpha), delta r(y) = (delta(r)) * sin(alpha)
Explanation:
Well it's a simple rule I guess...
Answer:
Explanation:
From the question;
We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.
We are to calculate the following task, i.e. to determine the electric field at the distances:
a) at 4.75 cm
b) at 20.5 cm
c) at 125.0 cm
Given that:
the charge (q) = 33.3 nC/m
= 33.3 × 10⁻⁹ c/m
radius of rod = 5.75 cm
a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.
Then, the electric field will be zero.
b) The electric field formula 
E = 1461.95 N/C
c) The electric field E is calculated as:
E = 239.76 N/C
Gamma rays then x rays then UVA rays then visible light then IR then radio waves (from highest to lowest frequency).
<span>The answer is C. This is called polarization of light by reflection. The sunlight is reflected at a parallel angle from on the surface plane of the water from which it bounces from. The glare is due to this polarization of sun beams at an angle with respect to the viewer. </span>
Explanation:
The total energy of an aircraft flying in the atmosphere can be calculated using equation 1. [2]
E = ½ m v2 + mgh
A Boeing 737-300 has a maximum takeoff weight of 5.65 × 104 kg, a cruise altitude of h = 10,195 m, and cruise speed of 221 m/sec. Inserting these numbers into the above equation, we obtain 7.03 GJ for the energy at cruise conditions. [3] However, the engines mounted onto the wings of the plane are required to provide additional energy per time, power, in order to keep the aircraft flying at a constant altitude and speed
Work is the energy needed to apply a force to move an object a particular distance, where force is parallel to the displacement. Power is the rate at which that work is done.
