Differentiate both sides of the equation of the circle with respect to 
, treating 
as a function of :
This gives the slope of any line tangent to the circle at the point 
.
Rewriting the given line in slope-intercept form tells us its slope is
In order for this line to be tangent to the circle, it must intersect the circle at the point such that
In the equation of the circle, we have
If 
, then 
, so we omit this case.
If 
, then 
, as expected. Therefore 
is a tangent line to the circle 
at the point (1, -2).
Answer:
PLace them one by one from big number to small and the middle number is the answer.
Step-by-step explanation:
Answer:
![f(x)=\sqrt[3]{x} \\a=5](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%20%5C%5Ca%3D5)
Step-by-step explanation:
Step-by-step explanation:
1) = 4ab
2) 12a2b
3) 8ab2
4) 6ab2
5) 12abc
6) 6ab2c
7) 16a2bc
8) 27abc
