Answer:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Step-by-step explanation:
The area of a sphere is given by the following formula:
In which A is the area, measured in cm², and r is the radius, measured in cm.
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.
This means that
Determine the rate of change in surface area when r = 20 cm.
This is when . So
Applying implicit differentiation.
We have two variables, A and r, so:
The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.
Radius = 24.49
Hope this helps! (If not sorry!)
Answer:
The answer is C=6p3 + 29p2 + 22p – 21
Step-by-step explanation:
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + 28p - 6p -21
= 6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
Answer:
what are you asking?
Step-by-step explanation:
Answer:
Cycle : Scooter = 15 : 30
or, Cycle : Scooter = 1 : 2
Step-by-step explanation: