Answer:
Explanation:
Firstly, when you measure the voltage across the battery, you get the emf,
E = 13.0 V
In order to proceed we have to assume that the voltmeter offers no loading effect, which is a valid assumption since it has a very high resistance.
Secondly, the wires must be uniform. So the resistance per unit length is constant (say z). Now, even though the ammeter has very little resistance it cannot be ignored as it must be of comparable value/magnitude when compared to the wires. This is can seen in the two cases when currents were measured. Following Ohm's law and the resistance of a length of wire being proportional to it's length, we should have gotten half the current when measuring with the 40 m wire with respect to the 20 m wire (
). But this is not the case.
Let the resistance of the ammeter be r
Hence, using Ohm's law we get the following 2 equations:
.......(1)
......(2)
Substituting the value of r from (2) in (1), we have,
which simplifying gives us, 
(which is our required solution)
putting the value of z in either (1) or (2) gives us, r = 0.5325 
Answer:
Varíe sus entrenamientos. Para muchos atletas, los ejercicios funcionales son el nombre del juego. ...
Realice un seguimiento y mida su rendimiento durante el entrenamiento. ...
Haga de la hidratación adecuada una prioridad. ...
Dedique suficiente tiempo a la recuperación. ...
Entrena tu cerebro. ...
Alimente su cuerpo de la manera correcta. ...
Considere agregar algunos suplementos a su dieta.
Explanation:
Answer:
The amount of work done in order to lift the box is 
Explanation:
Given the weight of each box is 
And the man lifts boxes at a height of 
We need to find the amount of work done.
The amount of work done is the product of applied force 
that causes the displacement 
.
In our problem force is and displacement is .
Now, work done
So, the amount of work done in order to lift the box is
The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.
