Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Super easy all you do is grab 3500*0.7306 which equals 2557.1 2557.1 is correct hope this helps
log(3x) = log(2x-4)
taking antilog of both sides:
3x = 2x - 4
3x - 2x = -4 [subtracting 2x from both sides]
x = -4
and we're done already!
Answer:
6
Step-by-step explanation:
A line that passes through the point (x,y), with a y-intercept of b and a slope of m, can be represented by the equation 
.
If a line has the slope of -0.5, then m=-0.5 and the equation of the line is
This line passes throughthe point (10,1), then the coordinates of this point satisfy the equation of the line:
and the equation of the line is
Since b=6, the y-intercept of the line is 6.
Answer:
x= -48 y =48
Step-by-step explanation:
-46 and 2 is -48 numbers away
