Answer:
W = M g weight of ball
T cos θ = W balancing vertical forces
T sin θ = F balancing horizontal forces
tan θ = F / W dividing equations
F = W tan θ when θ equals zero F equals zero
The the object that has the less mass will travel faster because let’s say for example the first object has the mass of M and the second object has the mass of 2M and if the momentum is equal so that means that we could divide M with M and we would get V1=2V2 (being V1 the velocity of the first mass and V2 the velocity of the second one) I hope I helped you out.
<h3><u>Given</u><u>:</u><u>-</u></h3>
Acceleration,a = 3 m/s²
Initial velocity,u = 0 m/s
Final velocity,v = 12 m/s
<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>
Calculate the time take by a car.
<h3><u>Solution:-</u><u> </u></h3>
According to the first equation of motion:
v = u + at
★ Substituting the values in the above formula,we get:
⇒ 12 = 0 + 3 × t
⇒ 12 = 3t
⇒ 3t = 12
⇒ t = 12/3
⇒ t = 4 sec
Answer:
t = 0.33h = 1200s
x = 18.33 km
Explanation:
If the origin of coordinates is at the second car, you can write the following equations for both cars:
car 1:
(1)
xo = 10 km
v1 = 55km/h
car 2:
(2)
v2 = 85km/h
For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:
The position in which both cars coincides is:
