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2 years ago

If a = -2, b = -6, c = -4, and d = -3, evaluate the following expressions.

Mathematics

1 answer:

abruzzese [7]2 years ago

6 0

It’s Has to be B because if you had the negative numbers you get -12

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Y=-1/2x+1 and y=1/3+6

-Dominant- [34]

If your teacher taught rise over run, then for the graphs:

y=-1/2x+1
start at y intercept of 1, then down 1, right 2 all the way, same for the other side but reversed.

y= 1/3+6
start at y intercept of 6, then up 1, right 3 all the way, same for the other side but reversed.

One solution: (-6,4)

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2 years ago

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Meredith's goal is to read one library book each week. On the first night, she read 14 pages more than of the pages in the book.

Murljashka [212]

Answer: A : 54

Step-by-step explanation:

1/7 of 280+14

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2 years ago

What is the answer to the equation 5x=2x+20?

Agata [3.3K]

I don't know. But I know how to find it. Let's work it out together:

5x = 2x + 20

Subtract 2x from each side: 3x = 20

Divide each side by 3 : x = 20/3 or ( 6 and 2/3 ).

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2 years ago

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4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

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2 years ago

Divide the following problem: 4/5 ÷ 37 Please give me a answer that helps.

Triss [41]

Answer:

4/185 or 0.0216...

Step-by-step explanation:

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2 years ago