Consider the function
, which has derivative
.
The linear approximation of
for some value
within a neighborhood of
is given by
Let
. Then
can be estimated to be
Since
for
, it follows that
must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function
. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
Answer:
4^15
Step-by-step explanation:
We multiply both exponents 3 and 5
So we get:
4^15
Hope this helps
Good Luck
0=6n- 36
6n-36
6 x-5-36
35-36
n=-1
I hope this help
Megan:
x to the one third power =
<span>x to the one twelfth power = </span>
<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>
<span>
Since </span>
then
Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4
Julie:
x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>
<span>
Since </span>
Then
Since
Then
Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
Answer:
18.9
Step-by-step explanation: